Brianna Perez, Rosa L. Parks School of Fine and Performing Arts

Brianna uses algebra to determine the costs of each pair of heels and each dress. She uses a

visual and verbal model, as well as a question to formulate a problem statement in order to

solve the answer. The presentation demonstrates how math can be applied practically to solve

real-world problems.

$80

$50

Verbal:

Brianna has two upcoming concerts to perform. On Friday she opens up a concert for Ariana Grande.

She needs two new pairs of heels and three brand new dresses. On Saturday, she opens up a concert for

Mariah Carey and needs one more pair of shoes and two more gowns. Her first purchase came out to

$800, and her second purchase came out to $500.

Question:

If her first purchase came out to $800 and her second purchase came out to by $500, what was the cost

of each pair of heels and each dress?

Equation:

Substitution:

2h + 3d = $800

2h+3d=800

h + 2d = $500

h+2d=500

Let "h" represent the cost of each heel.

1) h+2d=500

Let "d" represent the cost of each dress.

2d -2d

h= -2d+500

Elimination:

2) 2(-2d+500)+3d=800

2h+3d=800

-4d+1000+3d=800

h+2d=500

-d+1000=800

1) 2h+3d=800

-1000 -1000

-2(h+2d=500)

-d =-200

2) 2h+3d=800

-1

-1

-2h-4d=-1000

d= $200

-d =-200

3) h+2(200) =500

-1

-1

h= -2d+500

d = $200

-400 -400

3) h+2(200) =500

h = $100

h+400=500

h= $100 d= $200

400 -400

So Brianna spent $100 for each pair of heels and

h=$100

$200 for each dress she bought for the concerts.

4